7[x+1]=8[x-2]

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Solution for 7[x+1]=8[x-2] equation:


Simplifying
7[x + 1] = 8[x + -2]

Reorder the terms:
7[1 + x] = 8[x + -2]
[1 * 7 + x * 7] = 8[x + -2]
[7 + 7x] = 8[x + -2]

Reorder the terms:
7 + 7x = 8[-2 + x]
7 + 7x = [-2 * 8 + x * 8]
7 + 7x = [-16 + 8x]

Solving
7 + 7x = -16 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
7 + 7x + -8x = -16 + 8x + -8x

Combine like terms: 7x + -8x = -1x
7 + -1x = -16 + 8x + -8x

Combine like terms: 8x + -8x = 0
7 + -1x = -16 + 0
7 + -1x = -16

Add '-7' to each side of the equation.
7 + -7 + -1x = -16 + -7

Combine like terms: 7 + -7 = 0
0 + -1x = -16 + -7
-1x = -16 + -7

Combine like terms: -16 + -7 = -23
-1x = -23

Divide each side by '-1'.
x = 23

Simplifying
x = 23

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